Tolong dijawab…,… ​

integral

∫x^n dx = 1/(n + 1) x^(n + 1) + C

misal :

u = 3x + 7 → du = 3 dx

3x = u – 7

6x = 2u – 14

∫6x(3x + 7)⁸ dx

= ∫u⁸(2u – 14) du

= ∫(2u⁹ – 14u⁸) du

= 2/10 u¹⁰ – 14/9 u⁹ + C

= 1/5 (3x + 7)¹⁰ – 14/9 (3x + 7)⁹ + C