Misalkan p=3, q=-2, r=5 tentukan hasil dr bent

Jawaban:

p = 3

q = -2

r = 5

a. (p^q x p/r)^2 = (3^-2 x 3/5)^2

= {(1/3^2)(3/5)}

= {1/9 x 3/5}

= 3/45 = 1/15

b. (q + 3)^p (r – 3)^p-1 (p + 2)^p+2 = (-2 + 3)^3 (5 – 3)^3-1 (3 + 2)^3+2

= (1)^3 (2)^2 (5)^5

= 1 x 4 x 1125

= 4.500

c. (3p + 2q + r)^r+q+p = (3 x 3 + 2 x (-2) + 5)^5-2+3

= (9 -4 + 5)^6

= (10)^6

= 1.000.000

ket:

tanda ^ = pangkat

Penjelasan dengan langkah-langkah:

#Mogamembantuu:)