Hitunglah pH dari larutan 0,0004 M NH4OH jika Kb = 10-6 !tolong dong kak​

Penjelasan:

Rumus : -Log (√ Kb × Mb )

[OH-] = -Log (√ 10^-6 × [ 4 × 10^-4 M ] )

[OH-] = -Log (√ 4 × 10^-10 )

[OH-] = -Log ( 2 × 10^-5 )

[OH-] = 5- Log 2

pOH = 14 – (5- Log 2)

pOH = 14 – (4,7)

pOH = 9,3