( ^ { 3 } log ( 125 ) – ^ { 3 } log ( 5 ) div ( ^ { 3 } log ( 10 ) – ^ { 3 } log ( 2 )​

(³log 125 – ³log 5) / (³log 10 – ³log 2)

= (³log (125/5)) / (³log (10/2))

= ³log 25 / ³log 5

= ⁵log 25

= ⁵log 5²

= 2 . ⁵log 5

= 2