Hitunglahsudut antara vektor A dan B berikut ini,A = 3i – 2j + kB = 4i – 3j +2k

A = (3,-2,1); B (4, -3, 2)
A.B = 12 + 6 + 2 = 20
|A| = akar ( 9 + 4 + 1 ) = akar (14)
|B| = akar (16 + 9 + 4 ) = akar (29)
cos = 20 / ((akar 14)* (akar 29)) = 0,9925
sudut =  7