Tolong no 1…. soal PTN……

4^x = 6, berarti
2^2x = 6
(2^x)^2 = 6
2^x = √6

jadi :
(8^x + 8^-x) / (2^x + 2^-x) =
((2^x)^3 + 1/(2^x)^3) / (2^x + 1/(2^x)) =
((√6)^3 + 1/(√6)^3) / (√6 + 1/√6) =
(6√6 + 1/(6√6) / (6+1)/√6)) =
(216 + 1)/(6√6) x √6/7 =
(217√6) / (42√6) =
217/42 =
31/6