Tolongin pls saya udh nanya ke 3x​

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Tolongin pls saya udh nanya ke 3x​

Tolongin pls saya udh nanya ke 3x​

Jawab:

6. 13

7. 125frac{1}{27}

8. 22

9. a. sqrt[3]{49}

b. sqrt[4]{125}

10. gada soalnya

Penjelasan dengan langkah-langkah:

6. sqrt[3]{27^{2} } + sqrt[5]{32^{2} }

3^{2} + 2^{2} = 9 + 4 = 13

7. sqrt[3]{9^{-6} } + sqrt[2]{25^{3} }

sqrt{9^{-3} } + sqrt[2]{25^{3} }

3^{-3} + 5^{3} = frac{1}{3^{3} } + 125

125frac{1}{27}

8. sqrt[4]{81^{3} } – sqrt{25}

3^{3} – 5

27-5=22

9. a. sqrt[3]{7^{2} } = sqrt[3]{49}

b. sqrt[4]{5^{3} } = sqrt[4]{125}

Jawab:

6. 27^2/3 = (3^3)^2/3 = 3^3 = 27

32^2/5 = (2^5)^2/5 = 2^5 = 32

27+32=59

7. 9^-2 = sqrt{9\} = 3

25^-1/2 = sqrt{25}= 5

3+5 = 8

8. (3^4)^3/4=3^3=27

25^-1/2 = 1/sqrt{25} = 1/5 = 0,2

27-0,2 = 26,8

9.

a. sqrt[3]{7^2} = sqrt[3]{49} }

b. sqrt[4]{5^3} = sqrt[4]{125}