Metode campuran/gabungan (eliminasi – subtitusi)4x – 2y = 14y = ½ x-1​

4x – 2y = 14 … pers (1)

y = ½ x-1 … pers (2)

Metode eliminasi

y = ½x – 1

– x + 2y = – 2

4x – 2y = 14

_____________ +

3x = 12

x = 12/3

x = 4

Substitusi ke pers (2)

y = ½ x-1

y = ½ (4) – 1

y = 2 – 1

y = 1