Jika suku banyak f(x) = 2x3-5x2+x+7 dan f(x)= 2x4-3x3+px2+2x+4 dibagi (2x+1) memberikan sisa yang sama,tentukan nilai p!

Jika suku banyak f(x) = 2×3-5×2+x+7 dan f(x)= 2×4-3×3+px2+2x+4 dibagi (2x+1) memberikan sisa yang sama,tentukan nilai p!

$f(-frac{1}{2})=2(-frac{1}{2})^3-5(-frac{1}{2})^2+(-frac{1}{2})+7\ f(-frac{1}{2})=-frac{1}{4}-frac{5}{4}+frac{13}{2}\ f(-frac{1}{2})=5\\ g(-frac{1}{2})=2(-frac{1}{2})^4-3(-frac{1}{2})^3+p(-frac{1}{2})^2+2(-frac{1}{2})+4\ g(-frac{1}{2})=frac{1}{8}+frac{3}{8}+frac{p}{4}+3\ g(-frac{1}{2})=frac{1}{8}+frac{3}{8}+frac{2p}{8}+frac{24}{8}\ g(-frac{1}{2})=frac{28+2p}{8}\ \ f(-frac{1}{2})=g(-frac{1}{2})\ 5=frac{28+2p}{8}\ 40=28+2p\ p=6$