Bantu dong yang bisa​

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Bantu dong yang bisa​

Bantu dong yang bisa​

f^(x) = (x-1)/5

f^-1(x) = 5x + 1

g^-1(x) = (3-x)/2 = (-x+3)/2

g(x) = -2x+3

(f^-1 o g) (x) = 5(-2x+3)+1 = -10x +16

(f^-1 o g) ^-1 (x) = (x-16)/-10 = (-x +16)/10

(f^-1 o g)^-1 (2) = (-2 +16)/10 = 14/10 = 7/5