Tolong dong plisssssss.......

Tolong dong plisssssss…….

diket = AB = 18

AC = 15

BE = 25

ditanya = Luas Permukaan?

jawab =

1. mencari sisi tegak segitiga

$x ^{2} = 15^{2} - 9^{2} \ x^{2} = 225 - 81 \ x ^{2}= 144 \ x = sqrt{144} = 12$

2. menghitung luas permukaan

Rumus = 2×L.alas+K.alas×tinggi prisma

= 2×(1/2×a×t)+(ab+bc+ac)×t.prisma

= 2×(1/2×18×12)+(18+15+15)×25

= 2×108+48×25

= 216+1200

= 1416 cm2

semoga membantu:)