Diketahui f(x) = x2 – 4x + 2 dan g(x) = 3x = 5 makan f o g(-1) adalah

F(x) = x^2 – 4x + 2
g(x) = 3x + 5

maka, (fog)(x)
= f(g(x))
= (3x + 5)^2 – 4(3x + 5) + 2
= 9x^2 + 30x + 25 – 12x – 20 + 2
= 9x^2 + 18x + 7

jadi, nilai (fog)(-1) adalah :
= 9(-1)^2 + 18(-1) + 7
= 9 – 18 + 7
= -2

semoga membantu

Jawab:

Diketahui f(x) = x² – 4x + 2 dan g(x) = 3x + 5 makan f o g(-1) adalah?

Penjelasan:

_________

(fog)(x) = f(g(x))

(fog)(x) = (3x + 5)² – 4(3x + 5) + 2

(fog)(x) = 9x²+ 30x + 25 – 12x – 20 +2

(fog)(x) = 9x²+ 30x – 12x + 25 – 20 +2

(fog)(x) = 9x² + 18x + 7

Maka,

(fog)(-1) = 9x² + 18x + 7

(fog)(-1) = 9(-1)² + 18(-1) + 7

(fog)(-1) = 9 – 18 + 7

(fog)(-1) = -9 + 7

(fog)(-1) = -2

Semoga bermanfaat-,