Tolong dong yg senior bantu jawab dong besok uda di kumpul entar aku follow deh ​

Posted on

Tolong dong yg senior bantu jawab dong besok uda di kumpul entar aku follow deh ​

Tolong dong yg senior bantu jawab dong besok uda di kumpul entar aku follow deh ​

limit tak hingga

L = lim x→∞ √(ax² + bx + c) – √(px² + qx + r)

a = p L = (b – q)/2√a

nilai c diabaikan

a.

lim x→∞ √(x² + 6x) – (x – 4)

= lim x→∞ √(x² + 6x) – √(x – 4)²

= lim x→∞ √(x² + 6x) – √(x² – 8x + 16)

= (6 – (-8))/2√1

= 14/2

= 7

b.

lim x→∞ (3x – 1) – √(9x² – 8x + 1)

= lim x→∞ √(3x – 1)² – √(9x² – 8x + 1)

= lim x→∞ √(9x² – 6x + 1) – √(9x² – 8x + 1)

= (-6 – (-8))/2√9

= 2/(2.3)

= 1/3

c.

a < p L = – ∞

lim x→∞ √(4x² + 3x – 2) – (3x + 2)

= lim x→∞ √(4x² + 3x – 2) – √(3x + 2)²

= lim x→∞ √(4x² + 3x – 2) – √(9x² + 12x + 4)

= – ∞

d.

a > p L = + ∞

lim x→∞ (2x – 3) – √(x² – 3x + 2)

= lim x→∞ √(2x – 3)² – √(x² – 3x + 2)

= lim x→∞ √(4x² – 12x + 9) – √(x² – 3x + 2)

= + ∞

e.

lim x→∞ (x – 2) – √(x² – 4x + 3)

= lim x→∞ √(x – 2) – √(x² – 4x + 3)

= lim x→∞ √(x² – 4x + 4) – √(x² – 4x + 3)

= (-4 – (-4))/2√1

= 0/2

= 0