Diketahui sinus a=3 /5 nilai a adalah…​

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Diketahui sinus a=3 /5 nilai a adalah…​

CARA 1=⬇⬇

sinA = 3/5

cosA = -4/5

cosB = -3/5

sinB = 4/5

*inget kuadran 2 → sin (+) & cos (-)

sin2A = 2sinA.cosA

sin2A = 2.(3/5).(-4/5)

sin2A = -24/25

cos2A = cos²A – sin²A

cos2A = (-4/5)² – (3/5)²

cos2A = (16-9)/25

cos2A = 7/25

sin(2A+B) = sin2A.cosB + cos2A.sinB

sin(2A+B) = (-24/25)(-3/5) + (7/25)(4/5)

sin(2A+B) = 72/125 + 28/125

sin(2A+B) = 100/125

sin(2A+B) = 4/5

CARA 2=⬇⬇

sin a = 3/5 → y/r

x = √(r² – y²)

x = √(5² – 3²)

x = √(25 – 9)

x = √16

x = 4

tan a

= y/x

= 3/4

CARA 3=⬇⬇

Kuadran II yang bernilai positif hanya sin dan cosec.

Sin A = depan/miring=3/5

Depan = 3

Miring = 5

Samping = √5²-3²=√16=4

Tan A = depan/samping=-3/4

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Jawab:

a = 36,87°

Penjelasan dengan langkah-langkah:

Sin a = frac{3}{5}

sin a = 0,6

a = Arc sin 0,6 = 36,87°