Hitung normalitas berikuta. 4,5 gram alumunium klorida dalam 150 ml larutan
Jawaban Terkonfirmasi
AlCl₃
Mr = 133,5
ek = 3
wt = 4,5 gram
V = 150 mL
N = ……………….?
BE = Mr/ek
= 133,5/3
= 44,5
N = wt/BE x 1000/V
= 4,5/44,5 x 1000/150
= 0,1 x 6,67
= 0,667 normal