Kk bantuin butuh banget

Kk bantuin butuh banget

Penjelasan dengan langkah-langkah:

1) tipot sb x = (1,0) dan (3,0)

$f(x) = k(x - x1)(x - x2) \ f(x) = k(x - 1)(x - 3)$

melalui (-1,-16)

substitusi

$- 16 = k( - 1 - 1)( - 1 - 3) \ - 16 = k( - 2)( - 4) \ - 16 = 8k \ k = frac{ - 16}{8} = - 2$

maka

$f(x) = - 2(x - 1)(x - 3) \ = - 2( {x}^{2} - 4x + 3) \ = - 2 {x}^{2} + 8x - 6$

menyinggung sb x (-3,0)

$f(x) = k(x + {3)}^{2} + 0 \ f(x) = k(x + {3)}^{2}$

melalui (1,-8)

substitusi

$- 8 = k( {1 + 3)}^{2} \ - 8 = 16k \ k = frac{ - 8}{16} = - frac{1}{2}$

maka

$f(x) = - frac{1}{2} (x + 3 {)}^{2} \ = - frac{1}{2} ( {x}^{2} + 6x + 9)$

atau

$= frac{ - {x}^{2} - 6x - 9 }{2}$

titik puncak (5,-4)

$f(x) = k(x - {5)}^{2} - 4$

melalui (3,-12)

substitusi

$- 12 = k(3 - {5)}^{2} - 4 \ - 12 + 4 = 4k \ - 8 = 4k \ k = frac{ - 8}{4} = - 2$

maka

$f(x) = - 2(x - {5)}^{2} - 4 \ = - 2( {x}^{2} - 10x + 25) - 4 \ = - 2 {x}^{2} + 20x - 50 - 4 \ = - 2 {x}^{2} + 20x - 54$