Hitunglah volume 11 gram gas co2 di ukur pada keadaan STP (Ar c=12 , o=16)

Jawaban:

Mencari Mr gas

Mr CO₂ = (Ar C) + (Ar O × 2)

Mr CO₂ = 12 + (16 × 2)

Mr CO₂ = 12 + 32 = 44 gram/mol

Mencari mol gas

n gas CO₂ = m / Mr

n gas CO₂ = 11 gram / (44 gram/mol)

n gas CO₂ = 0,25 mol

Volume gas dalam keadaan STP

n gas CO₂ = V gas / 22,4

V gas CO₂ = n × 22,4

V gas CO₂ = 0,25 mol × 22,4

V gas CO₂ = 5,6 Liter

~Semoga membantu~