Bantuin soal nomor 3

Bantuin soal nomor 3

Jawab:

$M=left[begin{array}{cc}2&3\4&5\end{array}right]$

Penjelasan dengan langkah-langkah:

$K=left[begin{array}{cc}1&2\3&4\end{array}right] ,L=left[begin{array}{cc}2&0\0&2\end{array}right] ,I=left[begin{array}{cc}1&0\0&1\end{array}right] \Misal,M=left[begin{array}{cc}x&y\z&w\end{array}right] \K+L-M^{T}=I\left[begin{array}{cc}1&2\3&4\end{array}right] +left[begin{array}{cc}2&0\0&2\end{array}right]-left[begin{array}{cc}x&y\z&w\end{array}right] ^{T}=left[begin{array}{cc}1&0\0&1\end{array}right]$

$left[begin{array}{cc}3&4\3&6\end{array}right]-left[begin{array}{cc}x&z\y&w\end{array}right]=left[begin{array}{cc}1&0\0&1\end{array}right] \ left[begin{array}{cc}(-x+3)&(-z+4)\(3-y)&(-w+6)\end{array}right] =left[begin{array}{cc}1&0\0&1\end{array}right] \-x+3=1,x=2\-z+4=0,z=4\-y+3=0,y=3\-w+6=1,w=5\M=left[begin{array}{cc}2&3\4&5\end{array}right]$