Tentukan persamaan kuadrat yg akar-akarnya 3/4 dan 4/3 !!!

X1=3/4… x=3/4…. x-3/4=0
x2=4/3…x=4/3…..x-4/3=0

(x-3/4) (x-4/3)=0
x2-4/3x-3/4x+12/12=0
x2-25/12x+1=0… ×12.
12×2-25x+12=0…

cara 2 :
x1=3/4… x2=4/3
x1+x2=3/4+4/3=25/12
x1.x2=3/4×4/3=12/12=1
persamaan :
x2-(x1+x2)x+x1.x2=0
x2-(25/12)x+1=0
x2-25/12x+1=0… ×12
12×2-25x+12=0