300 k = derajat Reamur = derajat Fahrenheit​

Posted on

300 k = derajat Reamur = derajat Fahrenheit​

Jawaban:

Derajat Reamur:

= t°R =  tt frac{4}{5} (K – 273)

=  tt frac{4}{5} . 27

=  tt frac{108}{5}

= bold color {violet}{21,6°R}

Derajat Fahrenheit:

= t°F =  tt frac{9}{5} (K – 273) + 32

=  tt frac{9}{5} . 27 + 23

= 48,6 + 32

= bold color{purple}{80,6°F}

 colorbox{lime}{SEMOGA : MEMBANTU}

color{aqua}{hugeboxed{colorbox{violet}{areathasyifa}{}}}