Metode substitusi ×+4y=122×+3y=14

Metode substitusi ×+4y=122×+3y=14

Penjelasan dengan langkah-langkah:

$x + 4y = 12 \ x = 12 - 4y$

$2x + 3y = 14 \ maka : kita : rubah : x : nya \ 2(12 - 4y) + 3y = 14 \ 24 - 8y + 3y = 14 \ 24 - 5y = 14 \ 5y = 10 \ y = 2 \$

$x = 12 - 4y \ x = 12 - 4 times 2 \ x = 4$

Jawaban:

MENCARI Y

x + 4y = 12 (P1)

2x + 3y = 14 (P2)

(diambil dari persamaan 1/P1)

x = -4y + 12

maka digunakan di persamaan 2/P2 karena P1 sudah dipakai

2x + 3y = 14

2(-4y + 12) + 3y = 14

-8y + 24 + 3y = 14

-8y + 3y = 14 – 24

-5y = -10

5y = 10

y = 10/5

y = 2

MENCARI X

x + 4y = 12 (P1)

2x + 3y = 14 (P2)

x + 4y = 12 (P1)

4y = -x + 12

y = -1/4x + 3

2x + 3y = 14 (P2)

2x + 3(-1/4x + 3) = 14

2x + -3/4x + 9 = 14

8x + (-3x) + 36 = 56 (dikali 4)

5x + 36 = 56

5x = 56 – 36

5x = 20

x = 20/5

x = 4.