.   Hitunglah pH larutan berikut. a.   Larutan 500 mL amonia 0,1 M (Kb =   4 × 10–5).

#[OH-] = akar Kb x M = akar 4×10-5 x 10-1 =akar 4×10-6 = 2×10-3
#pOH = -Log[OH-]
= -log(2×10-3) = 3 -log 2
#PH = 14- pOH = 14 – 3-log 2 = 11+log 2

[OH-] = akar Kb x M = akar 4×10^-5 x 10-1 =akar 4×10^-6 = 2×10^-3

pOH = -Log[OH-]
= -log (2×10-3) = 3 -log 2

PH = 14- pOH = 14 – 3-log 2 = 11+log 2