Tentukan pH larutan jika diketahui H+=2×10^-5
PH=-logH⁺
=-log 2 x 10⁻⁵
= 5-log 2
=5- 0,30
=4.7
pH= 4.7
[H+] = 2×10^-5
pH = -log 2×10^-5
= 5 – log 2
= 5 – 0,3
= 4,7
*maaf jika jawaban kurang tepat. Semoga membantu:)
Tentukan pH larutan jika diketahui H+=2×10^-5
PH=-logH⁺
=-log 2 x 10⁻⁵
= 5-log 2
=5- 0,30
=4.7
pH= 4.7
[H+] = 2×10^-5
pH = -log 2×10^-5
= 5 – log 2
= 5 – 0,3
= 4,7
*maaf jika jawaban kurang tepat. Semoga membantu:)