Jika f'(x)=3xpangkat 2 -4x+2.untuk x=2 fungsi F bernilai 6.fungsi f (x) adalah…

Penyelesaian:

f'(x) = 3x^2 – 4x + 2

∫ (3x^2 – 4x + 2) dx

= (3/3) x^3 – (4/2) x^2 + 2x + C

= x^3 – 2x^2 + 2x + C

f(2) = 6

x^3 – 2x^2 + 2x + C = 6

8 – 8 + 4 + C = 6

4 + C = 6

C = 2

maka f(x) = x^3 – 2x^2 + 2x + 2

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu

Kode: 11.2.10

Kata Kunci: integral, rumus f (x)