Find the solution of each of the following equations!

a. 25 – 4y = 6y + 15
b. -5x -4y + 10 = 1
c. 3 (2p – 2) = 5p + 3
d. $frac{2x + 7}{5}$ – $frac{x - 3}{2}$ = $frac{3}{10}$

Find the solution of each of the following equations!

A. -4y-6y = 15-25
-10y = -10
   y = -10/-10
   y=1
b. -5x-4y+10=1
   -5x -4y +10 -1 =0
   -5x-4y+9=0 / 5x+4y+9 =0
c. 3(2p-2) = 5p +3
   6p -6 = 5p +3
   6p -5p =3+6
   p = 9
d. maaf lupaa caranya

A. 25-4y=6y+15
  25-15=6y+4y
  10=10y
  y= $frac{10}{10}$
  y=1

b. -5y-4y+10=1
-9y=1-10
-9y=-9
  9y=9
y= $frac{9}{9}$
y=1
c. 3(2p-2)=5p+3
   6p-6=5p+3
6p-5p=3+6
p=9
d. $frac{2x+7}{5}$ - $frac{x-3}{2}$ = $frac{3}{10}$
   $frac{4x+7}{10}$ – $frac{5x-3}{10}$ = $frac{3}{10}$
$frac{4x-5x+7-3}{10}$ = $frac{3}{10}$
$frac{-x+4}{10}$ = $frac{3}{10}$
30=-10x+40
10x=40-30
x= $frac{10}{10}$
x=1