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6) [H+] = 2 x 10^-5 x 10/20
= 10^-5
[OH-] = 10^-14/10^-5
= 10^-7
7) [OH-] = 10^-5 x 200/200
= 10^-5
pOH= 5
pH = 9
8) CH3COOH + NaOH => CH3COONa + H2O
m 50 mmol 40 mmol
r 40 mmol 40 mmol 40 mmol 40 mmol
s 10 mmol - 40 mmol 40 mmol
[H+] = 10^-5 x 1/4
= 2,5 x 10^-6
pH = 6 – ㏒ 2,5
9) pH = 5
10^-5 = 10^-5 x 0,4/mol garam
mol garam = 0,4
CH3COOH + NaOH => CH3COONa + H2O
m 0,4 mol 0,2x mol
r 0,2x mol 0,2x mol 0,2x mol
s (0,4-0,2x) mol – 0,4 mol
0,2x = 0,4
x = 2 L
10) pH = 9
pOH = 5
10^-5 = 10^-5 x 25/mol garam
mol garam = 25
NH3 + HCl => NH4Cl
m 25 mol 0,1x mol
r 0,1x mol 0,1x mol 0,1x mol
s (25-0,1x)mol - 25 mol
0,1x = 25
x = 250 L
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