Nilai dari sin 105 derajat dikurang sin 15 derajat adalah

sin 105

= sin (60 + 45)

=sin 60 cos 45 + cos 60 sin 45

= 1/2√3 1/2√2 + 1/2 1/2√2

=1/4√6 + 1/4√2

sin 15

= sin (45 – 30)

=sin 45 cos 30 – cos 45 sin 30

=1/2√2 1/2√3 – 1/2√2 1/2

= 1/4√6 – 1/4√2

sin 105 + sin 15

= 1/4√6 + 1/4√2 – (1/4√6 – 1/4√2)

= 1/4√6 + 1/4√2 – 1/4√6 + 1/4√2

= 1/2√2

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