Jika f(x)= x²+3×-5 tentukan nilai f(-2)

Jika f(x)= x²+3×-5 tentukan nilai f(-2)

f(x) = x² + 3x – 5

f(-2)

= (-2)² + 3(-2) – 5

= 4 + (-6) – 5

= 4 – 6 – 5

= – 2 – 5

$f(x) = {x}^{2} + 3x - 5 \ \ f( - 2) = { - 2}^{2} + 3( - 2) - 5 \ f( - 2) = 4 + ( - 6) - 5 \ f( - 2) = ( - 2) - 5 \ f( - 2) = - 7$

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