F(-5)=-27 dan f(-3)=5, maka f(0)= …

Bentuk fungsi umum adalah f(x) = ax + b
f(-5) = -27
f(-5) = -5a + b
f(-3) = 5
f(-3) = -3a + b

-5a + b = -27
-3a + b = 5
—————– –
-2a = -32
a = 16
substitusi nilai a = 16 ke persamaan -3a + b = 5
-3(16) + b = 5
-48 + b = 5
b = 5 + 48
b = 53

maka
f(x) = 16x + 53
f(0) = 16(0) + 53
f(0) = 0 + 53
f(0) = 53