1. (2x – 1)(3x+7)
2. (1 – 3x)(3+2y)
3. (p-3)(p-4)
4. (2a + b)(p – 3q)
5. (4x + 3)²
6. (-2q + 1)²
7. (2y — 3z)²
8. (4x + 2y)²
Uraikan bentuk aljabar berikut.
Jawab:
Penjelasan dengan langkah-langkah:
1. (2x – 1)(3x+7)
6×2 + 14x – 3x – 7 = 6×2 + 11x – 7
2. (1 – 3x)(3+2y)
3 + 2y – 9x – 6xy = -9x + 2y – 6xy + 3
3. (p-3)(p-4)
p2 – 4p – 3p + 12 = p2 – 7p + 12
4. (2a + b)(p – 3q)
2ap – 6aq + bp – 3bq
5. (4x + 3)²
(4x + 3)(4x + 3)
16×2 + 12x + 12x + 9 = 16×2 + 24x + 9
6. (-2q + 1)²
(-2q + 1)(-2q + 1)
4q2 – 2q – 2q + 1 = 4q2 – 4q + 1
7. (2y — 3z)²
(2y – 3z)(2y – 3z)
4y2 – 6yz – 6yz + 9z2
4y2 – 12yz + 9z2
8. (4x + 2y)²
(4x + 2y)(4x + 2y)
16×2 + 8xy + 8xy + 4y2
16×2 + 16xy + 4y2