Uraikan bentuk aljabar berikut.

Jawab:

Penjelasan dengan langkah-langkah:

1. (2x – 1)(3x+7)

6×2 + 14x – 3x – 7 = 6×2 + 11x – 7

2. (1 – 3x)(3+2y)

3 + 2y – 9x – 6xy = -9x + 2y – 6xy + 3

3. (p-3)(p-4)

p2 – 4p – 3p + 12 = p2 – 7p + 12

4. (2a + b)(p – 3q)

2ap – 6aq + bp – 3bq

5. (4x + 3)²

(4x + 3)(4x + 3)

16×2 + 12x + 12x + 9 = 16×2 + 24x + 9

6. (-2q + 1)²

(-2q + 1)(-2q + 1)

4q2 – 2q – 2q + 1 = 4q2 – 4q + 1

7. (2y — 3z)²

(2y – 3z)(2y – 3z)

4y2 – 6yz – 6yz + 9z2

4y2 – 12yz + 9z2

8. (4x + 2y)²​

(4x + 2y)(4x + 2y)

16×2 + 8xy + 8xy + 4y2

16×2 + 16xy + 4y2