Jika h(x)=2x+1, g(x)=x-5 dan f(x)=3x tentukan (h°f°g)(3)
(2x+1)(x-5)(3x)
hfg(x)=6x^3-27x^2-5x
hfg(3)=162-243-15
hfg(3)=-96
(hofog)(3) = h(f(g(3))) =h(f(3-5) =h(f(-2))=h((3(-2))=h(-6)=2(-6)+1=-12+1=-11
Jika h(x)=2x+1, g(x)=x-5 dan f(x)=3x tentukan (h°f°g)(3)
(2x+1)(x-5)(3x)
hfg(x)=6x^3-27x^2-5x
hfg(3)=162-243-15
hfg(3)=-96
(hofog)(3) = h(f(g(3))) =h(f(3-5) =h(f(-2))=h((3(-2))=h(-6)=2(-6)+1=-12+1=-11