Kak tolong dibantu no3 terimakasih banyak

Jawaban:

11 + log 1,6

Penjelasan:

3. mol = M x V

mmol NH2OH = 400 x 0,1 = 40 mmol

mmol (NH2)2SO4 = 250 x 0,1 = 25 mmol

[OH-] = Kb . ( mmol basa / mmol garam )

=> 10^-3 . ( 40 / 25 )

=> 1,6×10^-3 M

pOH = – log 1,6×10^-3

pOH = 3 – log 1,6

pH = 14 – ( 3 – log 1,6 )

pH = 11 + log 1,6