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Penyelesaian

A=left[begin{array}{ccc}1&2\4&5end{array}right]

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|A| = (5 . 1) – (4 . 2) = 5 – 8 = -3

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Adj A = left[begin{array}{ccc}5&-2\-4&1end{array}right]

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A⁻¹ = 1 / |A| . ajd A

A⁻¹ = – 1 / 3 . left[begin{array}{ccc}5&-2\-4&1end{array}right]

A⁻¹ = left[begin{array}{ccc}-frac{5}{3} &frac{2}{3} \frac{4}{3} &-frac{1}{3} end{array}right]

Penjelasan dengan langkah-langkah:

sfbegin{gathered} A=left[begin{array}{ccc}1&2\4&5end{array}right] \ \ end{gathered}

A^-1 = 1/ad – bc

A^-1 = 1/(1 × 5) – (2 × 4) [5 (-2)]

[(-4) 1]

A^-1 = 1/(5 – 8) [5 (-2)]

[ (-4) 1]

A^-1 = -⅓ [5 (-2)]

[ (-4) 1]

a {}^{ - 1} = begin{bmatrix} - frac{5}{3} & frac{2}{3} \ frac{4}{3} & - frac{1}{3} end{bmatrix}