Mohon dibantu jawabb ya kakkkk

Hk.Kekekalan Energi

mgh1 + 1/2.mv1² + 1/2.I.ω1² = mgh2 + 1/2.mv2² + 1/2.I.ω2²

Di puncak mula mula diam Ek = 0.

Di dasar Ep =0

mgh1 = 1/2.mv2² + 1/2.I.ω2²

mgh1 = 1/2.mv2² + 1/2.(2/5.m.R²).(v2²/R²)

mgh1 = 1/2.mv2² + 1/5.m.v2²

gh1 = 1/2.v2² + 1/5.v2²

gh1 = 7/10 . v2²

v2² = 10gh1 / 7

v2 = √(10.10.28/7)

v2 = √400

v2= 20 m/s