Tolong banget ya kakkk

Penjelasan dengan langkah-langkah:

no.13

²log(6 – ²logx) + 1 = ²log(²logx)

²log(6 – ²logx) + ²log2 = ²log(²logx)

²log(6 – ²logx)(2) = ²log(²logx)

(6 – ²logx)(2) = ²logx

12 – 2²logx = ²logx

12 = 3²logx

4 = ²logx

x = 2⁴

x = 16

.

no.14

ˣlog2x = 1 – ¹⁰log2

ˣlog2x = 1 – ¹⁰log2

ˣlogx + ˣlog2 = ˣlogx – ¹⁰log2

ˣlog2 = – ¹⁰log2

ˣlog2 = – ²log2/²log10

ˣlog2.²log10 = – ²log2

ˣlog10 = – 1

10 = x⁻¹

10 = 1/x

x = 1/10

.

no.15

³logx + ³log(2x – 3) < 3

³log(x(2x – 3) < ³log3³

x(2x – 3) < 3³

2x² – 3x – 9 < 0

(2x + 3)(x – 3) < 0

x = – 3/2

x = 3

+.+.+.+.+.+ – – – – – – – +.+.+.+.+.+

…………-3/2……………3…………….

x > -3/2 dan x < 3