Minta bantuannya guys… kalo isa kasih cara ya guys… makasih

²log 3 = x
³log 5 = y
maka
²log 3 . ³log 5
= ²log 5 = xy
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¹⁵log 20
= log 20 / log 15
= ²log 20 / ²log 15
= ²log(4.5) / ²log(3.5)
= (²log4 + ²log5) / (²log3 + ²log5)
= (2 + xy) / (x + xy)
= (2 + xy) / x(1 + y)

LogAritMa

²log 3 = x
³log 5 = y

15'log 20
= ³log 20 / ³log 15
= (³log (2² × 5)) / (³log (3 × 5))
= (2 . ³log 2 + ³log 5) / (³log 3 + ³log 5)
= (2 . 1/x + y) / ( 1 + y)
= (2 + xy) / x(1 + y)
= (2 + xy) / (x + xy) ✔