Fungsi f dan g dirumuskan f(x) = 3x² – 4x + 6 dan g(x) = 2x – 1

(fog)(x) = f(g(x))
=> 101 = 3(2x – 1)^2 – 4(2x – 1) + 6
=> 0 = 3(4x^2 – 4x + 1) – 8x + 4 + 6 – 101
=> 0 = 12x^2 – 12x + 3 – 8x – 91
=> 0 = 12x^2 – 20x – 88
=> 0 = 3x^2 – 5x – 22
=> (3x – 11)(x + 2) = 0
=> x = 11/3 atau x = -2