Tolong jawab pakai jalan ya

Tolong jawab pakai jalan ya

$sqrt{x - 1} > sqrt{14 - 2x} \ x - 1 > 14 - 2x \ x + 2x > 14 + 1 \ 3x > 15 \ x > 5 \ syarat : numerus \ x - 1 > 0 \ x > 1 \ 14 - 2x > 0 \ - 2x > - 14 \ x < 7$
Hp = ( 5 < x < 7)