Diketahui R1=12ohm R2=4ohm R3=6ohm R4=4ohm E=16volt I=… kuat arus listrik yg melewati hambatan R2 adalah

jawabanya 2 Ampere

pembahasan

R paralel = 1/R1 +1/R2 + 1/R4

R total = R paralel + R2

R paralel = 1/12 + 1/6 + 1/4

= 1/12 + 2/12 + 3/12

= 6/12 = 12/6 = 2 ohm

R total = 2+4 = 6 ohn

I pada R2 = E/ R total

= 12/6

= 2 Ampere