F(x) = x² + 2x – 4g(x) = x² – 4x – 6 (g o f) (1) ?
Penyelesaian
f(x) = x² + 2x – 4
g(x) = x² – 4x – 6
(gof)(1)
g(f(1))
g((1)² + 2(1) – 4)
g(1 + 2 – 4)
g(3 – 4)
g(-1)
(-1)² – 4(-1) – 6
1 + 4 – 6
5 – 6
-1
Detail Jawaban
- Mapel: Matematika
- Kelas: 10 (1 SMA)
- Materi: Fungsi
- Kode Soal: 2
- Kode Kategorisasi: 10.2.3
Penyelesaian:
f(x)=x²+2x-4
g(x)=x²-4x-6
(g o f)(1)=g(f(1))
. =g((1)²+2(1)-4)
. =g(1+2-4)
. =g(3-4)
. =g(-1)
. =(-1)²-4(-1)-6
. =1+4-6
. =-1
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