Tolong bantu dijawab terimakasihh

Tolong bantu dijawab terimakasihh

Jawaban:

1. ω = 2π/T = 2π/0.5 = 4π rad/s

a. y = A sin ωt = (0.01 sin 4π) meter

b. a max = Aω² = 0.01 (4π)² = 0.16 π² m/s²

2. y = 0.04 sin 20π t

A = 0.04 m

ω = 20π

a. saat y max , a = a max = Aω² = 0.04 (20π)² = 16π² m/s²

b. v = Aω cos ωt

= 0.04 × 20π cos 20π t

= (0.8π cos 20π t) m/s

$v : max = 80 : cm/s \ v : max = A times ω \ 80 = 6 times ω \ ω = frac{40}{3} rad/s \ y = A : sin : ωt \ 3 = 6 : sin : ωt \ sin : ωt = frac{1}{2} \ ωt = 30⁰ = frac{pi}{6} \ v = A times ω times cos : ωt \ v= 6 × frac{40}{3} × frac{1}{2} sqrt{3} \ = 40 sqrt{3} : m/s$

$frac{T1}{T2} = frac{2pi sqrt{ frac{m1}{k}} }{2pi sqrt{ frac{m2}{k}} } \frac{T1}{T2} = sqrt{ frac{m1}{m2}} \ frac{2}{T2} = sqrt{ frac{800}{200}} \ T2 = 1 : s$

$y = 3 \ y = : A : sin : ωt \ 3 = 5 : sin : ωt \ sin : ωt = : frac{3}{5} \ω = frac{2pi}{T} = frac{2pi}{0.5pi} = 4 : rad/s$

$a = - A {ω}^{2} : sin : ωt \ a= - 5 times {4}^{2} times frac{3}{5} = - 48 :m/ {s}^{2}$

$∑F = m times a = 0.5 times ( - 48) \∑F= - 16 :N$

$v : max = A times ω = 0.18 times 4 \ v : max = 0.72 :m/s \ Ek : max = frac{1}{2} times m times {v}^{2} \ = frac{1}{2} times 0.4 times {0.72}^{2} = 0.10368 :Joule$

Jawaban:

1.a gerakan yang lurus

b10

Penjelasan:

semoga membantu