Cari akar akar persamaan kuadrat x²-13x+12=0​

X²-13X +12=0

X²- X – 12X + 12 =0

X(X-1) – 12(X-1)=0

(X-1) x (X-12)=0

X-1=0

X-12=0

X¹=1. Atau X²=12

Penjelasan dengan langkah-langkah:

X²-13x+12=0

a=1 b= -13 c= 12

x²-13x= -12

x²= -13/a x = -12/a

x²+ -13/1x + (-13/2a)² = -12/1+(-13/2a)²

x²+ -13/1x + (-13/2)² = -12/1+(-13/2)²

(X+ -13/4)²= -12/1+169/4

(X+ -13/4)²= -48/4+169/4

(X+ -13/4)²= 121/4

X+ -13/4= +_ √121/4

X+ -13/4= +_ 11/2

X1= -13/4+11/2= -13/4+11/4=-2/4= -1/2

X²= -13/4-11/2= -13/4-11/4=-24/4= -6

X1= -1/2

X2= -6