4 x kuadrat dua kurang 8 X kurang 3 sama dengan nol

4 x kuadrat dua kurang 8 X kurang 3 sama dengan nol

Jawab:

x =

(2+√7)/2

dan (2-√7)/2

Penjelasan dengan langkah-langkah:

Solve for x,

4x²-8x-3=0

Pake rumus ini=

$x_{1,:2}=frac{-bpm sqrt{b^2-4ac}}{2a}$

4x²-8x-3=0

a = 4, b = -8, c = -3

Maka:

$x=frac{-left(-8right)pm sqrt{left(-8right)^2-4* :4left(-3right)}}{2* :4}\\x=frac{8pm sqrt{left(-8right)^2+4cdot :4cdot :3}}{2cdot :4}\\x=frac{8pm sqrt{112}}{2* :4}$

Cari x1

$x_{1}= frac{8+ sqrt{112}}{2* :4}\\x_{1}= frac{8+4sqrt{7}}{8}\\x_{1}= frac{4left(2+sqrt{7}right)}{8}\\x_{1}= frac{2+sqrt{7}}{2}$

Cari x2

$x_{2}= frac{8- sqrt{112}}{2* :4}\\x_{2}=frac{8-4sqrt{7}}{8}\\x_{2}=frac{4left(2-sqrt{7}right)}{8}\\x_{2}=frac{2-sqrt{7}}{2}$

Jawaban:

x1 = (2+√7)/2

x2 = (2-√7)/2