dicampur dengan 300 mL HC10,01 M.
Berapakah pH masing-masing
larutan sebelum dicampur dan
berapakah pH larutan?
Sebanyak 200 mL H2SO4 0,002 M
(H2SO4)
[H+] = a × Ma
[H+] = 2 × 0,002 M
[H+] = 0,004 M atau 4 × 10^-3 M
pH = -Log [H+]
pH = -Log [4 × 10^-3]
pH = 3-Log4
pH = 3 – 0,6
pH = 2,4
(HClO)
[H+] = a × Ma
[H+] = 1 × 1 × 10^-1
[H+] = 1 × 10^-1
pH = -Log [H+]
pH = -Log [1 × 10^-1]
pH = 1-Log1
pH = 1
pH setelah di campur :
Rumus :
= (V1 × M1) + (V2 × M2) / V. Total
= (200 mL × 0,002 M) + (300 mL × 0,1 M) / 500 mL
= (0,2 mmol) + (30 mmol) / 500 mL
= (30,2 mmol) / 500 mL
= 0,0604 mmol
pH = -Log [6,04 × 10^-2]
pH = 2 – Log 6,04
pH = 1,22