When a purple solution of KMnO4 is added to a different unknown, a brown precipitate forms. What can be said about this unknown?​

KMnO4 is a very strong oxidator. When oxidator is react and form brown precipitate, it should be MnO2. MnO2 appear because KMnO4 is reducted. So the different unknown is a reductor.

kalau benar kasih jawaban terbaik yah:)

kalo salah komen:)