Mesin carnot bekerja diantara suhu 300K dan 393K .berapakah efisiensi mesin itu

Diketahui :
T1 = 393 K
T2 = 300 K

Ditanya : E = ?

Jawab :
E = [ 1 – (T2/T1 )] x 100%
= [ 1 – (300/393)] × 100%
= [393/393 – 300/393] × 100%
= 93/393 × 100 %
=23,664 %