Jika f(x) = x2 + 1 dan g(x) = 2x – 2 maka (f°g) (x) – (g°f)(x)

=> Fungsi Komposisi

(fog)(x) = f(2x – 2)

(fog)(x) = (2x – 2)(2x – 2) + 1

(fog)(x) = 4x^2 – 8x + 4 + 1

(fog)(x) = 4x^2 – 8x + 5

(gof)(x) = g(x^2 + 1)

(gof)(x) = 2(x^2 + 1) – 2

(gof)(x) = 2x^2 + 2 – 2

(gof)(x) = 2x^2