Tolong bantu saya!!!​

Jawaban:

titik berat = luas segiempat – luas segitiga kosong

segiempat

A1 = pxl = 6×4 = 24

x1 = ½p =  3

y1 = ½l = 2

segitiga

A2 = ½ alas x tinggi = ½ x 4 x 3 = 6

x2 = 1/3 tinggi = 1/3 x 3 = 1

y2 = ½ alas = 2

titik berat

x = (A1x1 – A2x2)/(A1-A2)

x = (24×3 – 6×1)/(24-6)

x = 66/18 = 3,67

y = (A1y1 – A2y2)/(A1-A2)

y = (24×2 – 6×2)/(24-6)

y = 36/18 = 2

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