air sebanyak 600 gram bersuhu 20°c dicampur air 300 gram bersuhu 65°c hitung suhu akhir campuran air tersebut!​

m₁ = 600 gram

m₂ = 300 gram

T₁ = 20°C

T₂ = 65°C

Maka, Tcampuran (Tc)

Tc = x

» Q₁ = Q₂

» m₁ × C₁ × (Tc – T₁) = m₂ × C₂ × (T₂ – Tc)

» 600(x – 20) = 300(65 – x)

» 600(x – 20) = 300(-x + 65)

» 600x – 12.000 = 300x + 19.500

» 600x + 300x = 19.500 + 12.000

» 900x = 31.500

» x = 31.500/900

» x = 35°C

Jadi, suhu akhir campuran air yaitu 35°C