Tentukan pH larutan 0,02 mol CH3COOH dengan 0,1 mol (CH3COO)2Ba. Jika Kb = 1.10-5

N CH3COOH = 0,2 mol
n (CH3COO)Ba = 0,1 mol
Ka = 1 × 10^-5

[H+] = Ka × n asam / n garam
= 1 × 10^-5 × 0,2 mol / 0,1 mol
= 2 × 10^-5

pH = – log [H+]
= – log (2 × 10^-5)
= 5 – log 2
= 4,7